Question on: WAEC Physics - 2014
A car starts from rest and covers a distance of 40m in 10s. Calculate the magnitude of its acceleration
A
0.25ms-2
B
0.80ms-2
C
3.20ms-2
D
4.00ms-2
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Correct Option: B
S = ut + \(\frac{1}{2} at^2\)
40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2
40 = 0 x 10 + \(\frac{1}{2}\) x a x 102
50a = 40
a = \(\frac{40}{50}\)
= 0.8ms-2
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